Reverse of a String and Number of Vowels - Java Program - Scanner

Reverse of a String and Number of Vowels  

 Scanner -Java Program

Program: Reverse.java

import java.util.Scanner;
class Reverse 
{
public static void main(String args[])
{
 String string,reverseString = "";
 int vowelCount=0;
 
   Scanner sc=new Scanner(System.in);
   System.out.print("Enter the word: ");
   string= sc.nextLine();
   
   for(int i=string.length()-1;i>=0;i--)
   {
    char ch=string.charAt(i);
    reverseString+=ch;
    if(ch=='A'||ch=='a'||ch=='E'||ch=='e'||ch=='I'||ch=='i'||ch=='O'||ch=='o'||ch=='U'||ch=='u')
    vowelCount++;
   }
   
   
   System.out.println("Reverse: "+reverseString+"\nNumber of vowels: "+vowelCount);
   
}
}

Output:

Enter the word: 2k8cse
Reverse: esc8k2
Number of vowels: 1

FIND REVERSE OF EACH WORD IN A STRING - Assembly Language - MASM

Program:

        ;FIND REVERSE OF EACH WORD IN A STRING

.model small

.stack 200h

.data

msg1 db 10,13,'Enter the string:$'

msg2 db 10,13,'Reverse of the string:$'

newline db 10,13,' $'

buff db 60 dup(?)

flag db 0

stackempty db 1

.code

print macro msg

push ax

push dx

mov ah,09h

mov dx,offset msg

int 21h

pop dx

pop ax

endm

.startup

print msg1

print newline

mov si,offset buff

mov cx,0

mov bx,0

nxtchar:

mov ah,01h

int 21h

inc bx

cmp al,' '

je popy

cmp al,0dh

je popy

mov ah,0

push ax

mov stackempty,0

inc cx

jmp nxtchar

popy:

cmp stackempty,1

je stackkaali

cmp al,0dh

jne noflag

mov flag,1

noflag:

pop ax

mov [si],al

inc si

loop noflag

inc si

mov stackempty,1

cmp flag,1

je display

jmp nxtchar

stackkaali:

inc si

jmp nxtchar

display:

print msg2

print newline

mov si,offset buff

mov cx,bx

dispnxt:mov dh,0

mov dl,[si]

mov ah,2

int 21h

inc si

loop dispnxt

.exit

End

OUTPUT

F:\>rev

Enter the string:

kerala is called gods own country

Reverse of the string:

alarek si dellac sdog nwo yrtnuoc

Reverse of a String - Assembly Language - MASM

REVERSE OF A STRING

Program:

.model small

.stack 200h

.data

   msg1 db 10,13,"Enter string:",10,13,'$'

   msg2 db 10,13,"Reverse of the string is:",10,13,'$'

   arr db 20 dup(?)

.code

   print MACRO msg

   PUSH AX

   PUSH DX

   MOV AH,09H

   MOV DX,offset msg

   INT 21H

   POP DX

   POP AX

   ENDM

.startup

   print msg1

   mov arr,18

   mov dx,offset arr

   mov ah,0ah

   int 21h

   lea dx,msg2

   mov ah,09h

   int 21h

   mov ch,0h

   mov cl,arr[1]

   mov di,cx

   inc di

l1:

   mov dl,arr[di]

   mov ah,02h

   int 21h

   dec di

   loop l1

  .exit

End

Output:

F:\>revv

Enter string:

PALINDROME

Reverse of the string is:

EMORDNILAP

Sum of Digits & Number of Digits - Assembly Language - MASM

Number of Digits, Sum of Digits & Reverse of a Number

 

Program:

.model small

.stack 200h

.data

   msg1 db "Enter the number::$"

   msg2 db 'Sum of digits is::$'

   msg3 db 'No. of digits is::$'

   msg4 db 10,13,"Reverse of the given number is::$"

   newline DB 10,13, ' $'

   sum dw 0

   NO dW 0

   cnt dw 0

   arr db 20 dup(?)

.code

   print MACRO msg

   push ax

   push dx

   mov ah,09h

   mov dx,offset msg

   INT 21H

   pop dx

   pop ax

ENDM

.startup

   print msg1

   call readnumtoAX

   print msg4

   mov cx,ax

   mov BX,10

   mov si,offset arr

   mov di,offset arr

DV1:

   mov ax,cx

   mov dh,00

   mov dl,00

   div BX

   mov cx,ax

   inc NO

   mov al,dl

   mov [si],al

   mov ah,00

   call displayAX

   inc si

   add SUM,DX

   mov ax,cx

  cmp    AX,0

  jne DV1

  mov AX,NO

   print newline

   print msg3

   CALL displayAX

   MOV AX,SUM

   print newline

   print msg2

CALL displayAX

  print newline

   ;mov cx,NO

  ;dis:

   ; mov ah,00

   ; mov al,arr[di]

   ; CALL displayAX

   ;inc di

   ;loop dis

.EXIT

readnumtoAX PROC NEAR

   PUSH BX

   PUSH CX

   MOV CX,10

   MOV BX,00

back:

   MOV AH,01H

   INT 21H

   CMP AL,'0'

   JB skip

   CMP AL,'9'

   JA skip

   SUB AL,'0'

   PUSH AX

   MOV AX,BX

   MUL CX

   MOV BX,AX

   POP AX

   MOV AH,00

   ADD BX,AX

   JMP back

skip:

   MOV AX,BX

   POP CX

   POP BX

   RET

readnumtoAX ENDP

displayAX PROC NEAR

   PUSH DX

   PUSH CX

   PUSH BX

   PUSH AX

   MOV CX,0

   MOV BX,10

back1:

   MOV DX,0

   DIV BX

   PUSH DX

   INC CX

   OR AX,AX

   JNZ back1

back2:

   POP DX

   ADD DL,30H

   MOV AH,02H

   INT 21H

   LOOP back2

   POP AX

   POP BX

   POP CX

   POP DX

   RET

displayAX ENDP

END

Output:

F:\>unt

Enter the number::7835

Reverse of the given number is::5387

No. of digits is::4

Sum of digits is::23

Sum of Digit & Reverse of a Number - C Program

Program:
#include<stdio.h>
//#include<conio.h>
void main()
{
    int r=0,n,sum=0,d;
    printf("Enter the number:");
    scanf("%d",&n);
    while(n>0)
    {
      d=n%10;
      sum=sum+d;
      r=(r*10)+d;
      n=n/10;
    }
    printf("\n sum of digits= %d",sum);
    printf("\n Reverse=%d",r);
    printf("\n");
//getch();
}

Output:
nn@linuxmint ~ $ gcc c24.c
nn@linuxmint ~ $ ./a.out
Enter the number:15

 sum of digits= 6
 Reverse=51
nn@linuxmint ~ $